Re: Re: Regex Match for 3 repeated word characters

Abigail is correct and as such is my time for fun with math (woohoo!).

Number of possible passwords lost by forcing one character to be alpha
+: 1111100000000
Number of possible passwords lost by forcing one character to be numer
+ic: 9.92461065750669e+16
Number of possible passwords lost by forcing at least one character to
+ be alpha and one to be numeric: 9.92472176750669e+16
[download]

Hmmm...that's quite a few passwords.

Updated: Doing math after 10PM isn't one of my strong points.

antirice
The first rule of Perl club is - use Perl
The ith rule of Perl club is - follow rule i - 1 for i > 1

Comment on Re: Re: Regex Match for 3 repeated word characters Download Code

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Re: Re: Re: Regex Match for 3 repeated word characters by jryan (Vicar) on May 08, 2003 at 05:22 UTC
The number isn't quite that high. Consider: `Total Possible - Actual Possible = Total Lost (36^8 + 36^9 + 36^10 + 36^11 + 36^12) - ((36^6 + 36^7 + 36^8 + 36^9 + +36^10)1026) = TL 36^6 * ((36^2 + 36^3 + 36^4 + 36^5 + 36^6) - ((36^0 + 36^1 + 36^2 + 36 +^3 + 36^4)1026)) = TL 36^6 * (2,238,976,080 - 449,177,300) = TL 3,896,002,369,298,350,080 = Total Lost` [download] Although 19 digits is hardly a trivial amount (-:	[reply] [d/l]

Replies are listed 'Best First'.

Re: Re: Re: Regex Match for 3 repeated word characters
by jryan (Vicar) on May 08, 2003 at 05:22 UTC

The number isn't quite that high. Consider:

Total Possible - Actual Possible = Total Lost
(36^8 + 36^9 + 36^10 + 36^11 + 36^12) - ((36^6 + 36^7 + 36^8 + 36^9 + 
+36^10)*10*26) = TL
36^6 * ((36^2 + 36^3 + 36^4 + 36^5 + 36^6) - ((36^0 + 36^1 + 36^2 + 36
+^3 + 36^4)*10*26)) = TL
36^6 * (2,238,976,080 - 449,177,300) = TL
3,896,002,369,298,350,080 = Total Lost
[download]

Although 19 digits is hardly a trivial amount (-:

[reply]
[d/l]