in reply to shift vs. @_ (where @_ evaluates to 1)
my $strFoo = @_ evaluates @_ in scalar context. Arrays in scalar context return their size. What you want is my ($strFoo) = @_ which evaluates @_ in list context returning its values.
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Re: Re: shift vs. @_ (where @_ evaluates to 1)
by P0w3rK!d (Pilgrim) on May 09, 2003 at 18:47 UTC |