Re: Referencing string: Can't use string as a SCALAR ref

P0w3rK!d,
Ok - completely misread the question the first time. Try taking a look at File::Basename, but here's a RE to try if you are 100% of your filenames and know there will be no gotchas.

my $strFileA = 'C:\foo\a\b\c\123.xml';
my ($filename) = ($strFileA =~ /\\([^\\]*)$/);
print $filename,"\n";
[download]

Cheers - L~R

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Re: Re: Referencing string: Can't use string as a SCALAR ref by P0w3rK!d (Pilgrim) on May 12, 2003 at 18:33 UTC
Thank you :) I have it working now. I'm just curious if I can do it a better way. -P0w3rK!d	[reply]
Re: Re: Re: Referencing string: Can't use string as a SCALAR ref by antirice (Priest) on May 12, 2003 at 19:23 UTC
There is a better way to do it. (Which happens to be Limbic~Region's first suggestion.) As an added bonus, it also makes the code more portable to other OS's (as long as you have the script setup a directory or something rather than hard-coding it.) `use File::Basename; my $file = basename($filestring); print $file,$/;` [download] antirice The first rule of Perl club is - use Perl The ith rule of Perl club is - follow rule i - 1 for i > 1	[reply] [d/l]
Re: Re: Referencing string: Can't use string as a SCALAR ref by P0w3rK!d (Pilgrim) on May 12, 2003 at 18:17 UTC
$strFileA comes in as a function parameter.	[reply]