in reply to Simple Math Puzzle...
Brute force here is at worst 10^5. But since digit3 depends on digit1, and digit5 depends on digit4 there are only three 'loose' digits, or 10^3 possibilities.
You could brute-froce the 1000 combinations on paper ;)
-jack
ps, you can find old Ecco columns by typing 'ecco' in the search box on ddj.
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