###Begin Perl###
#!/usr/local/bin/perl
$prg = "./testers.sh";
$ret_val = <`$prg`>;
print "\n\n$ret_val:From Perl Not BASH Script\n\n";

###End Perl####
###Begin Bash###
#!/usr/local/bin/bash
`/bin/cp /wantstats.sh /newstats.sh`
echo Success
###End Bash###
[download]

Not here!

$ ./p1


`./testers.sh`:From Perl Not BASH Script

$
[download]

I think you don't know what thos `` mean! In your testers.sh I see:

`/bin/cp /wantstats.sh /newstats.sh`
[download]

Luckily /bin/cp doesn't have any STDOUTput! Just go ahead and enter:

`echo ls`
[download]

You will get the output of ls not the text "ls"!

this is because `xxx` first execute xxx and then execute the output of xxx!

No don't execute but try to imagine what this will do:

`echo rm -rf \*`
[download]

I do know what the backticks mean...that is not the problem. I found out where the 'problem' is. Now...this is with the exact programs that I just posted on my last node. The reason we had a discrepency, IMO, is the versions of Perl we are using. You are right...the program does not work...at least not with perl, v5.6.1. I was working with perl, v5.00503, and it *DOES* work. I promise, I've ran it at least twenty times by now trying to replicate what you're getting. I ran it under 5.6.1 and there you go...I bow out, it's not working. BUT...If you have a 5.00503 install please try it so that I may have some redemption ;o).