in reply to How to convert time in perl?
sub pick2mmddyy { my ($day, $mo, $year) = (gmtime(($_[0]-732)*86400))[3,4,5]; return sprintf("%02d/%02d/%02d", $mo+1, $day, $year%100); } print pick2mmddyy(11982), "\n";
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Re: Re: How to convert time in perl?
by cbro (Pilgrim) on Jun 05, 2003 at 14:04 UTC | |
by Steve4950 (Initiate) on Jun 05, 2003 at 14:30 UTC | |
by Thelonius (Priest) on Jun 05, 2003 at 15:40 UTC |