You want the modulus operator (%), same as in Java. I.e., perl -e 'print(5 % 3, $/)'. See perlop.

5%3 = 2

What we used to call a remander in grade school.

If you really mean division, then I don't grok what you mean. Because 5/3 is either 1.66666 or 1, floating point or integer respectively.

If you still really want 5/3 = 2 in perl then:

use strict;
print " 5/3 = 2 \n"; # coder flunked math
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Nothing is too wonderful to be true
-- Michael Faraday

Not math, but perl -le 'print sprintf("%.0f", 5/3);'.

Try perldoc -q round for a more complete answer.

Update: monsieur_champs++ might well be right, but the AnonyMonk's question is unclear. 5/3 rounded to the nearest integer is 2, but so is 5 % 3 :-)

Dear BazB

Our anonymous fellow was asking about the remainder operator (%). What I see here is a (useful, indeed) number formatting tip. Please correct this one. ++BazB for his sincere and humble signature asking for other monks to teach him.

=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Just Another Perl Monk

Did you want the remainder (i.e. the modulo, as given by other posters) or just the result rounded up? You can get the latter with:

use POSIX qw/ceil/;
print POSIX::ceil( 5/3 );
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With Perl 5.8, you can do the following:

use integer;
my $result = 5/3;
print "$result\n";
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Otherwise, you can do something like:

my $result = int(5/3);
print "$result\n";
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Update: I believe my head is screwed on backwards today. ;-) Both result in 1. D'oh!

public class temp{
        public static void main(String[] args){
                int a=5;
                int b=3;
                int c=a/b;
                System.out.println(c);
        }
}
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