for (s = cmd; *s; s++) {
if (*s != ' ' && !isALPHA(*s) && strchr("$&*(){}[]'\";\\|?<>~`\n",
+*s)) {
if (*s == '\n' && !s[1]) {
*s = '\0';
break;
}
/* handle the 2>&1 construct at the end */
if (*s == '>' && s[1] == '&' && s[2] == '1'
&& s > cmd + 1 && s[-1] == '2' && isSPACE(s[-2])
&& (!s[3] || isSPACE(s[3])))
{
char *t = s + 3;
while (*t && isSPACE(*t))
++t;
if (!*t && (dup2(1,2) != -1)) {
s[-2] = '\0';
break;
}
}
doshell:
PerlProc_execl(PL_sh_path, "sh", "-c", cmd, (char*)0);
return FALSE;
}
}
So, when it is checking for shell meta characters, if it finds " 2>&1" at the end (without any shell meta characters before that) and if dup2(1,2) != -1, then it strips the " 2>&1" and avoids the shell.
- tye
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