Re: Re: filtering folder path using regex.

Thanks Sir,

the $path =~ /^(\w):\\(^\\+)\\?/ worked for me, but what I don't understand how does it get the $2 value? There is no “.” or “\w” in the second parenthesis. Oh well, as long as it works…

Comment on Re: Re: filtering folder path using regex.

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Re: Re: Re: filtering folder path using regex. by tcf22 (Priest) on Jul 13, 2003 at 18:55 UTC
I think you were talking about this one: `$path =~ /^(\w):\\([^\\]+)\\?/;` [download] In this one `[\\]` would match just backslashes, but with the ^, `[^\\]`, matches all characters Except backslashes, and because of the `+`, it matches as much as possible up to the 1st backslash. $2 is populates, because the character class (ie. [^\\]) is in parenthesis, which happens to be the second set of them, so therefore is stored in $2	[reply] [d/l] [select]
Re: Re: Re: Re: filtering folder path using regex. by blackadder (Hermit) on Jul 14, 2003 at 20:57 UTC
Spot on with your explanation kind sir. `[] and ^` means all Except backslashes,...I confused it with ^ as an anchor or start of a word boundary....I should’ve been more careful when constructing a Regex expressions!… Thanks for reminding me.... & I should always keep practice coding.	[reply] [d/l]