in reply to Avoiding the Use of @ISA = qw(Foo::Bar);

I'm not sure what you're trying to avoid. It's is precisely necessary to set @ISA to declare inheritance. What problem do you think you're trying to solve?

-- Randal L. Schwartz, Perl hacker
Be sure to read my standard disclaimer if this is a reply.

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Re: •Re: Avoiding the Use of @ISA = qw(Foo::Bar);
by hardburn (Abbot) on Jul 14, 2003 at 18:07 UTC

    I want an extra layer of indirection between me and @ISA, because I don't like assuming that @ISA was already empty when I said our @ISA = qw(Foo);. use base provides that layer and gives you a little extra stuff.

    ----
    I wanted to explore how Perl's closures can be manipulated, and ended up creating an object system by accident.
    -- Schemer

    Note: All code is untested, unless otherwise stated

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      Yes, but who else would set it, other than your definition of your module? You need to have one place in your program with a clear declaration of the inheritance of that class.

      -- Randal L. Schwartz, Perl hacker
      Be sure to read my standard disclaimer if this is a reply.

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