Re: Re: Converting MySQL datetime values to DateTime objects (regex)

what am i doing wrong here? i've tried it w/ and w/o the parens around the regexp.

use strict;
use warnings;

my $when = '2003-07-14 21:39:26.357';
my ( $yr, $mo, $day, $hr, $min, $sec ) =
    ( $when =~ /(\d{4})(\d\d)(\d\d)(\d\d)(\d\d)(\d\d)/ );
print "( $yr, $mo, $day, $hr, $min, $sec )\n";

__DATA__
Use of uninitialized value in concatenation (.) or string at C:\dev\sc
+ripts\reg.pl line 6.
Use of uninitialized value in concatenation (.) or string at C:\dev\sc
+ripts\reg.pl line 6.
Use of uninitialized value in concatenation (.) or string at C:\dev\sc
+ripts\reg.pl line 6.
Use of uninitialized value in concatenation (.) or string at C:\dev\sc
+ripts\reg.pl line 6.
Use of uninitialized value in concatenation (.) or string at C:\dev\sc
+ripts\reg.pl line 6.
Use of uninitialized value in concatenation (.) or string at C:\dev\sc
+ripts\reg.pl line 6.
( , , , , ,  )
[download]

can somebody help a (clueless) brother out?
Update:
cool cool cool- never knew you could return an array from a regexp. here's another way too:

my ( $yr, $mo, $day, $hr, $min, $sec ) = 
( $when =~ /(\d{4})\D*(\d\d)\D*(\d\d)\D*(\d\d)\D*(\d\d)\D*(\d\d)/ );
[download]

Comment on Re: Re: Converting MySQL datetime values to DateTime objects (regex) Select or Download Code

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Re: Re: Re: Converting MySQL datetime values to DateTime objects (regex) by dws (Chancellor) on Jul 14, 2003 at 20:52 UTC
`my $when = '2003-07-14 21:39:26.357'; my ( $yr, $mo, $day, $hr, $min, $sec ) = ( $when =~ /(\d{4})(\d\d)(\d\d)(\d\d)(\d\d)(\d\d)/ );` [download] You have to match all of the punctuation in your source string. E.g., to match `my $when = '2003-07';` [download] you would use `my ($yr,$mo) = $when =~ /^(\d\d\d\d)-(\d\d)/; ^` [download] Fixing the complete regex is a variation on this theme.	[reply] [d/l] [select]