Using "prototype" tricks in methods

v_thunder has asked for the wisdom of the Perl Monks concerning the following question:

I have a couple of methods that take a coderef, and I'd like to use the "prototype" trick to pass in a block instead of a sub as the first argument. The problem is, it's a method, so the first argument is $self.

Am I just out of luck?

Comment on Using "prototype" tricks in methods

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Re: Using "prototype" tricks in methods by bobn (Chaplain) on Jul 30, 2003 at 22:06 UTC
Prototypes don't work at all for methods, so I'd say yes, you are SOL. --Bob Niederman, http://bob-n.com	[reply]
Re: Using "prototype" tricks in methods by adrianh (Chancellor) on Jul 30, 2003 at 23:25 UTC
As everybody has already pointed out you're out of luck I'm afraid. Prototypes don't apply to methods. You'll just have to pass the subroutine explicitly like this: `$object->method( sub { ... } );` [download] (Note: you are actually passing a subroutine with the prototype too - it just looks like a block).	[reply] [d/l]
Re: Using "prototype" tricks in methods by diotalevi (Canon) on Jul 30, 2003 at 22:06 UTC
Wait for perl6.	[reply]
Re: Re: Using "prototype" tricks in methods by waswas-fng (Curate) on Jul 30, 2003 at 22:17 UTC
lol or if your deadline is before 2005, redesign. =) -Waswas	[reply]
Re: Using "prototype" tricks in methods by Anonymous Monk on Jul 30, 2003 at 23:12 UTC
Redesign. Forget prototypes. Shift off of the argument list and then use `ref()`, for example, to type-check the intended argument.	[reply] [d/l]