Re: Function call in a regular expression

Perl provides the (??{}) (This is a "postponed" regular subexpression) construct in regular expressions for the purpose you mention. For example:

$text =~ s|(??{chr 231})|c|gise;
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There is more information about the construct in perldoc perlre.

update: Note I am answering the question of:

I'd like to be able to call a function in the matching portion of substitution expression.

(though there are better solutions that do the same thing as the OP's example below).

-enlil

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Re: Re: Function call in a regular expression by sauoq (Abbot) on Jul 31, 2003 at 22:22 UTC
Be aware that this is an experimental feature. One of the other ways to do it might be more appropriate for production code. -sauoq "My two cents aren't worth a dime.";	[reply]
Re: Re: Function call in a regular expression by diotalevi (Canon) on Jul 31, 2003 at 22:40 UTC
Update: Oops, I misread Enlil's (??{}) as (?{}) which is very different. His original code works, it just isn't a great way to write that. Better to write it directly as \xe7. No, no this is wrong. (?{}) is zero width and is always true. That's no help to the person who just wants to get the character #231 into their regex. Some other nice monks noticed that you could write it in hex form \xe7 or BrowserUK's verbose (and slightly slower) `@{[ chr 231 ]}`.	[reply] [d/l]