Of course, we can do much worst than O(n^2). I present here a much better candidate for "the worst", the splatter sort, which will take on average O(n!). (Well, O(m!), where m is the number of distinct values among the n elements.)
This algorithm was inspired by many student assignments back when I was a corrector in university, where the student would do
while(list_isnt_sorted()) {
do_buggy_transform();
}
and claim their code was right because it eventually terminated with a sorted list...
A more advanced version would use a code ref to pass to is_sorted, so we could have different sort criteria like perl's sort routine does...
Just when you thought sorts couldn't get any worst :)
(Edit: D'oh! This isn't as bad as it could be. Since I check if the list is sorted before shuffling, this will unfortunately do quite well on already sorted data. Pessimizing the code further isn't too challenging an exercise, though :) )
# stolen from sauoq, who attributed it to perdoc -q shuffle: sub fisher_yates_shuffle { my $deck = shift; # $deck is a reference to an array my $i = @$deck; while ($i--) { my $j = int rand ($i+1); @$deck[$i,$j] = @$deck[$j,$i]; } } sub is_sorted { my $list_r = shift; my $prev=$list_r->[0]; for(my $i=1;$i<scalar @$list_r;++$i) { return 0 if $list_r->[$i]<$prev; $prev=$list_r->[$i]; } return 1; } # sort list passed by reference in place, returning # reference to sorted list # # takes n! time. sub splatter_sort { my $list_r=shift; while(!is_sorted($list_r)) { fisher_yates_shuffle($list_r); } return $list_r; }
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Re: Making bubble sort look good
by Anonymous Monk on Aug 04, 2003 at 20:32 UTC | |
by RMGir (Prior) on Aug 04, 2003 at 20:55 UTC |