Re: Remove lowest number

    my @d1s = sort { $b <=> $a } $d61 ;
    my @d2s = sort { $b <=> $a } $d62 ;
    my @d3s = sort { $b <=> $a } $d63 ;
    my @d4s = sort { $b <=> $a } $d64 ;
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What is the point of this? Sorting lone scalars, and putting them in one element arrays? What's the point of chomping $roll? I would write that as:

#!/usr/bin/perl

use strict;
use warnings;

my $tosses = 5;
my $dice   = 4;

foreach (1 .. $tosses) {
    my @rolls = sort {$b <=> $a} map {2 + int rand 5} 1 .. $dice;
    pop @rolls;
    my $sum = 0;
       $sum += $_ for @rolls;
    print "\n@rolls: $sum\n\n";
}
__END__
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And that includes finding the top-3 rolls and summing them.

Abigail

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Re: Re: Remove lowest number by ellem (Hermit) on Aug 06, 2003 at 17:04 UTC
First let's understand that I have no idea what I am doing and only a murky idea of what I want to do! OK I'll give you the chomp I think that had something to do with an older version of this. See mostly I make Perl read logs and take data from different sources and shove it all together. But I don't do this everyday and as such I suck at it. OK, so I thought: `my @num = (8, 9, 3, 5, 1, 2, 6, 7) ; my @all = sort { $b <=> $a } @num ;` [download] thus: `my $num5 = 5 ; my $num4 = 4 ; my $num3 = 3 ; my $num2 = 2 ; my @all = sort { $b <=> $a } $num4, $num2, $num5, $num3 ;` [download] So when I was writing this code: `my @d1s = sort { $b <=> $a } $d61 ;` [download] I thought I was sorting $d61 and I thought it might be hard to get at the lowest number inside $. Apparently I was wrong, but your code is over my head. `$sum += $_ for @rolls;` [download] Doesn't mean a lot to me. The whole $_ thing confuses me. UPDATE: I really looked at this answer, suggestion and I started commenting things out to see which part of my code was really useless. Here's what is left: #! /usr/local/bin/perl use diagnostics ; use warnings ; use strict ; use List::Util qw (sum) ; #not in the standard distro my $roll = 6 ; until ($roll == 0) { #rolls the dice 6 times $roll -- ; my @d61 = int(rand(5) + 2) ; #6 sided die with no 1 my @d62 = int(rand(5) + 2) ; my @d63 = int(rand(5) + 2) ; my @d64 = int(rand(5) + 2) ; my @all = sort #split line for looks { $b <=> $a } @d61, @d62, @d63, @d64 ; #sorts rolls #to prepare for pop @all ; #pop removing #the lowest roll my $sum = sum(@all) ; #before adding print "\n@all - $sum\n" ; } [download] -- ellem@optonline.net There's more than one way to do it, but only some of them actually work.	[reply] [d/l] [select]

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Re: Re: Remove lowest number
by ellem (Hermit) on Aug 06, 2003 at 17:04 UTC

my @num = (8, 9, 3, 5, 1, 2, 6, 7) ;
my @all = sort { $b <=> $a } @num ;
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my $num5 = 5 ;
my $num4 = 4 ;
my $num3 = 3 ;
my $num2 = 2 ;

my @all = sort { $b <=> $a } $num4, $num2, $num5, $num3 ;
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my @d1s = sort { $b <=> $a } $d61 ;
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$sum += $_ for @rolls;
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UPDATE:

#! /usr/local/bin/perl
use diagnostics ;
use warnings ;
use strict ;
use List::Util qw (sum) ;        #not in the standard distro

my $roll = 6 ;

until ($roll == 0) {            #rolls the dice 6 times  
    $roll -- ;
    
    my @d61 = int(rand(5) + 2) ;    #6 sided die with no 1
    my @d62 = int(rand(5) + 2) ;
    my @d63 = int(rand(5) + 2) ;
    my @d64 = int(rand(5) + 2) ;
    
    my @all = sort                 #split line for looks
    { $b <=> $a } @d61, @d62, @d63, @d64 ;    #sorts rolls 
                        #to prepare for
    pop @all ;                    #pop removing 
                            #the lowest roll
    my $sum = sum(@all) ;            #before adding
    
    print "\n@all - $sum\n" ; 
}
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