in reply to unix epoch date

Check out the built in localtime(). It takes an epoch seconds arguement, and returns an array consisting of various date / time parts. Depending on your calculations, the breakdown returned by localtime() can make the calculations easy.

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Re: Re: unix epoch date
by Anonymous Monk on Aug 08, 2003 at 16:18 UTC
    Yer, I've been working through that today, however I can't work out how I can translate 12272 as being today, if I user localtime I make today 1062975600 !!!
[reply]
      A day is 24 hours with 60 minutes with 60 seconds each. 
      perl -le 'print time() / (24*60*60)'

      [download]
      Alternatively, 
      perl -le 'print scalar localtime( 12272 * 24*60*60 )'
perl -le 'print scalar gmtime( 12272 * 24*60*60 )'

      [download]

      --
      [ e d @ h a l l e y . c c ]

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[d/l]
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        A day is 24 hours with 60 minutes with 60 seconds each.
        Well - *most* days...:)

        Ben.

[reply]
        Excellent, thanks for the help . .

        Rich

[reply]
      Where do you get 12272 from? is there some code snippet that is causing trouble, i need to know more of whats going on.
[reply]
      sorry I meant if I use localtime(). . .
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