Re: Given a tie object, get a tied hash (or scalar, or whatever)

Why do you have to use $obj in the call to Foo()? Shouldn't you simply use the %hash value to create %newhash?
The basic problem that I see is that $obj doesn't know anything about the class %hash was tied to, so there is no simple way to implement Foo($obj).

Comment on Re: Given a tie object, get a tied hash (or scalar, or whatever)

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Re: Re: Given a tie object, get a tied hash (or scalar, or whatever) by Dice (Beadle) on Aug 13, 2003 at 16:50 UTC
> The basic problem that I see is that $obj doesn't know anything about the class %hash was tied to No? What would ref($obj) return? Remember that $obj comes from `my $obj = tied(%hash);` [download] And the very def'n of tied is that it returns the underlying object that implements the tied thingy. Cheers, Richard	[reply] [d/l]