in reply to Simple concatenation of hashes

Here's a related question, perhaps suitable for meditation: If I initialize a hash with redundant keys, do I get predictable results? That is, are the following two examples equivalent?
%a = (one => 'eins', two => 'zwei', three => 'drei', one => 'uno'); %b = (one => 'eins', two => 'zwei', drei => 'drei'); $b{one} = 'uno';