Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:
My end goal is to actually replace the filenames blah and blah2 with an undetermined list ie maybe more, maybe less, of different filenames. I figured stripping out the filenames and then doing a glob of the files and then using appendChild to readd each of the child nodes using XML::XPath would do. Is this conceptually sane or is there some better way to do it?<blah> <datarec> <filename>blah</filename> <filename>blah2</filename> </datarec> </blah>
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•Re: XML::XPath
by merlyn (Sage) on Aug 18, 2003 at 23:25 UTC | |
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Re: XML::XPath
by BrowserUk (Patriarch) on Aug 19, 2003 at 00:46 UTC | |
by Matts (Deacon) on Aug 20, 2003 at 07:37 UTC | |
by BrowserUk (Patriarch) on Aug 20, 2003 at 08:41 UTC | |
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Re: XML::XPath
by dishwasher179 (Initiate) on Aug 19, 2003 at 01:55 UTC | |
by mirod (Canon) on Aug 19, 2003 at 08:27 UTC |