Re: Passing a reference to a subroutine in a constructor

I think this is what you want(untested)

my $collection = Collection->new({ 'sorter' => \&Sort::mysorter });

...

sub new
{
  my ($self, $options) = @_;
  .  .  .
  $self->{sorter} = $options->{sorter};
}
[download]

You actually pass the CODEREF into the constuctor, instead of using a soft reference.

Comment on Re: Passing a reference to a subroutine in a constructor Download Code

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Re: Re: Passing a reference to a subroutine in a constructor by DrSax (Sexton) on Aug 22, 2003 at 18:48 UTC
I get the same result when I do that. Is the execution of the sort method itself? `$self->{sorter}($keys);` [download] Dr. Sax	[reply] [d/l]
Re3: Passing a reference to a subroutine in a constructor by dragonchild (Archbishop) on Aug 22, 2003 at 20:11 UTC
`$self->{sorter}->($keys);` [download] Note the squigglies when de-referencing `$self` and the round parens when de-referencing the sort routine coderef. ------ We are the carpenters and bricklayers of the Information Age. The idea is a little like C++ templates, except not quite so brain-meltingly complicated. -- TheDamian, Exegesis 6 Please remember that I'm crufty and crochety. All opinions are purely mine and all code is untested, unless otherwise specified.	[reply] [d/l] [select]
Re: Re3: Passing a reference to a subroutine in a constructor by DrSax (Sexton) on Aug 22, 2003 at 20:24 UTC
Rob, It's always a pleasure to see a guy whose sig line is longer than his response... ;-) Brian (a.k.a. DrSax)	[reply]