Re: Defining an anonymous hash with slices and lists.

How is Perl to know that:

@{ qw/ one two three / } = (1..3)

is intended to be a hash declaration, not a list assignment?

Comment on Re: Defining an anonymous hash with slices and lists. Download Code

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Re: Re: Defining an anonymous hash with slices and lists. by davido (Cardinal) on Aug 27, 2003 at 21:50 UTC
Well, actually the following does create a hash: `my %hash; @hash{ qw/ one two three / } = ( 1..3 );` [download] And if you don't care about strictures, the `my %hash;` part can even be eliminated. The problem comes when trying to pluck one of its values while defining it, like this: `$someval = ${@hash{ qw/ one two three / } = ( 1..3 )}{two};` [download] And it only gets worse if you try to make it anonymous by removing the name "hash". Dave "If I had my life to do over again, I'd be a plumber." -- Albert Einstein	[reply] [d/l] [select]

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does

my %hash;
@hash{ qw/ one two three / } = ( 1..3 );
[download]

And if you don't care about strictures, the my %hash; part can even be eliminated.

The problem comes when trying to pluck one of its values while defining it, like this:

$someval = ${@hash{ qw/ one two three / } = ( 1..3 )}{two};
[download]

And it only gets worse if you try to make it anonymous by removing the name "hash".

Dave

"If I had my life to do over again, I'd be a plumber." -- Albert Einstein