Re: Re: Re: $a++ allowed by $a-- is not ! why?

but if we only allow either lower case or upper case (not both mixed), the problem nearly disappears:

As long as you can mix numbers with letters the problem remains.

or can you find a value for $z so that ++ $z is "0"? no, you can't.

What about -1?

But thanks, some good links there. :-)

---
demerphq

_{<Elian> And I do take a kind of perverse pleasure in having an OO assembly language...}

Comment on Re: Re: Re: $a++ allowed by $a-- is not ! why? Download Code

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Re^4: $a++ allowed by $a-- is not ! why? by kabel (Chaplain) on Sep 01, 2003 at 10:12 UTC
As long as you can mix numbers with letters the problem remains. no, the signature does not allow to mix letters with numbers. if we allowed this, that means: `++: /\A[a-z0-9]\z/ -> /\A[a-z0-9]\z/` [download] , what is the difference between this addition and the addition in a 36-ary number system? (have fun with this link) the only problem here is that the first character must not be a number, thus the awkward domains: `kabel@linux:~> perl my $num = "1hiho"; print ++ $num, $/; 2 kabel@linux:~>` [download] What about "-1"? "-1" is an illegal input. harhar. ;-)	[reply] [d/l] [select]
Re: Re^4: $a++ allowed by $a-- is not ! why? by demerphq (Chancellor) on Sep 01, 2003 at 11:02 UTC
the signature does not allow to mix letters with numbers. I think we are at cross purposes here. It does allow them to be mixed, you may have any set of letters followed by any set of numbers and ++ will "work". This means that you still have the problem we have been discussing as there is no mapping from 9 to 'a0' but there is a mapping from 'a0' to 9. --- demerphq _{<Elian> And I do take a kind of perverse pleasure in having an OO assembly language...}	[reply] [d/l]