And, in fact, it is the logical default for comparing junctions. It's basic set theory. Two sets are equivalent if they contain the same elements. What junctions do need is to see if one junction is a subset of another junction. This is equivalent to asking if every $foo in junction $bar is within the other junction $baz.
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We are the carpenters and bricklayers of the Information Age. The idea is a little like C++ templates, except not quite so brain-meltingly complicated. -- TheDamian, Exegesis 6 Please remember that I'm crufty and crochety. All opinions are purely mine and all code is untested, unless otherwise specified. | [reply] |