Re: Re: converting hash to shuffled array

Of all the wonderful responses I think this is the easiest one for me to understand and implement into my script. I do have a question or two about it and was wondering if you could help me figure them out.

Why is there a my $pair? I only see it being used in that one statement.

Why is there a @pair at the end when the previous line is giving it a value?

Thanks for your help everyone! I've noticed most of your scripts are very similar in nature which makes it easier. I didn't know you could do a @array = keys %db, that must be a lot easier on the server instead of doing a foreach loop.

"Age is nothing more than an inaccurate number bestowed upon us at birth as just another means for others to judge and classify us"

sulfericacid

Comment on Re: Re: converting hash to shuffled array

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Re: Re: Re: converting hash to shuffled array by BrowserUk (Patriarch) on Sep 12, 2003 at 04:19 UTC
Why is there a my $pair? I only see it being used in that one statement. Um! Cos I made a mistake! It should be @pair and now is:) Why is there a @pair at the end when the previous line is giving it a value? The previous line loops a random number of time setting the @pair to succesive key/value pairs from the hash. Once the loop stops, the last statement becomes the return value for the do block, and so the last key/value pair assigned to the array @pair, get assigned to the variables $name and $url. Examine what is said, not who speaks. "Efficiency is intelligent laziness." -David Dunham "When I'm working on a problem, I never think about beauty. I think only how to solve the problem. But when I have finished, if the solution is not beautiful, I know it is wrong." -Richard Buckminster Fuller If I understand your problem, I can solve it! Of course, the same can be said for you.	[reply]

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Re: Re: Re: converting hash to shuffled array
by BrowserUk (Patriarch) on Sep 12, 2003 at 04:19 UTC

Why is there a my $pair? I only see it being used in that one statement.

Um! Cos I made a mistake! It should be @pair and now is:)

Why is there a @pair at the end when the previous line is giving it a value?

The previous line loops a random number of time setting the @pair to succesive key/value pairs from the hash.

Once the loop stops, the last statement becomes the return value for the do block, and so the last key/value pair assigned to the array @pair, get assigned to the variables $name and $url.

Examine what is said, not who speaks.

"Efficiency is intelligent laziness." -David Dunham
"When I'm working on a problem, I never think about beauty. I think only how to solve the problem. But when I have finished, if the solution is not beautiful, I know it is wrong." -Richard Buckminster Fuller
If I understand your problem, I can solve it! Of course, the same can be said for you.

[reply]