Re: parsing question

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Re: Re: parsing question by Roger (Parson) on Sep 15, 2003 at 09:07 UTC
Hi Ab, but I have tested the following code, which were giving me the same test results on many test cases: `if ($str =~ /_test(?>\s+)(?!<)/) { print "test ok\n" } if ($str =~ /_test(?:\s+)(?!<)/) { print "test ok\n" }` [download] Could you please tell me as why the `/_test(?:\s+)(?!<)/` is wrong? I want to learn. Thanks!	[reply] [d/l] [select]
Re: parsing question by Abigail-II (Bishop) on Sep 15, 2003 at 11:36 UTC
As I said before, it was pointed out elsewhere in this thread. In one of my postings, I showed a program pointing out the differences. Please read the entire thread - it's not that there are 500 postings. Abigail	[reply]
Re: Re: parsing question by Roger (Parson) on Sep 16, 2003 at 01:14 UTC
Thanks Abigail, I have realised the problem of my mistake, where the double space is matched as "space + not <". My previous regular expression should really be written as `/_test\s+(?![\s\|<])/`, as "space not followed by another space or <". Thanks for your help!	[reply] [d/l]