vnpandey has asked for the wisdom of the Perl Monks concerning the following question:

Dear monks, In my programme the value of output record seperator is fixed as newline in the begining of the prgramme itself (This I verify as when I print it in the first executable line of programme).. I don't know how is it fixed like this by default?or I have fixed it some-how in my programme itself ? any-way I have not used it any-where in my programme except to print it in the first line executable line..Please help: - Thanks :V.N.Pandey

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Re: output record seperator!
by neshura (Chaplain) on Aug 27, 2000 at 10:14 UTC
    Doh! Updating because it is late and I misread...$\ is set to newline by default. You may choose to set it to something else. Check perlman:perlvar for more information.

    e-mail neshura

[reply]

      actually, $\ is set to undef by default. perhaps vnpandey's code is using a module that sets $\ before it is printed.

      i ran the following on my system and it showed me that $\ hadn't yet been set:

      perl -e "print '$\ undefined', $/ unless defined $\;"

      outputs (for me):

      $\ undefined

[reply]
[d/l]
Re: output record seperator!
by tye (Sage) on Aug 29, 2000 at 07:24 UTC

    Perhaps the script starts with "#!/usr/bin/perl -l"?

            - tye (but my friends call me "Tye")
[reply]

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