There are two approaches for this kind of question. Both involve examining the range operator a bit more closely.

Option 1 is to catch the return value of the range operator itself, which you now only use as a boolean.

if(my $cnt = /^ policy-map $ouputpol/ ... / policy-map/) {
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(Precedence of "..." is higher than the assignment.)

If you examine the contents of $cnt closely, you'll see it's a counter, with the numerical value 1 for the first line, 2 for the next... and as a string, it has a "E0" appended only for the very last line. So you can check it:

    print unless $cnt==1 || $cnt =~ /E/;
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Note that that suffix doesn't change the value of the number, while it's still a valid representation of it.

The second approach is to catch the return value of the left and right hand sides individually:

if(($my $first = /^ policy-map $ouputpol/) ... (my $last = / policy-ma
+p/)) {
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Note the extra parens. Here, $first will be true for the first line, and $last will be true for the last one. No additional check is necessary.

    print unless $first || $last;
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For the people who want a simple standalone test, without requiring something ressembling your data:

for my $i (1 .. 15) {
    if(my $cnt = $i==5 ... $i==10) {
        print "$i - $cnt\n";
    }
}
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which prints:

5 - 1
6 - 2
7 - 3
8 - 4
9 - 5
10 - 6E0

And the other one:

for my $i (1 .. 15) {
    if((my $first = $i==5) ... (my $last = $i==10)) {
        # note: $first will be undefined for any but the first line be
+cause of the 3 dots
        # and $last will be undefined for the first line
        local $^W;
        print "$i - $first / $last\n";
    }
}
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which prints:

5 - 1 / 
6 -  / 
7 -  / 
8 -  / 
9 -  / 
10 -  / 1