in reply to Uninitialized Value Warning
Hate to be so blunt but it means exactly what it says.
You never gave $count a value. To get rid of it you could set my $count=0, but I'm not sure what that'll do for you. The way you have this code it looks like you're only trying to print "1" ( $array[0] ) to myfile.txt.
What are you wanting this code to accomplish?
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Re: Re: Uninitialized Value Warning
by Anonymous Monk on Oct 22, 2003 at 21:33 UTC | |
by thelenm (Vicar) on Oct 22, 2003 at 23:06 UTC | |
by bobn (Chaplain) on Oct 22, 2003 at 22:30 UTC |