Re: Deriving pi and e

Apart from pg's and Abigail-II's comments, I couldn't resist golfing these down to:

1while($x||=3)-($x-=sin$x/cos$x);print"$x\n"
[download]

and:

1while($x||=2)-($x-=((log($x)-1)*$x));print"$x\n"
[download]

I particularly like the fact that it only uses 1 variable ;-)

Liz

Update:
Golfed some more by losing the seperate initial assignement of $x

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Re^2: Deriving pi and e by jdalbec (Deacon) on Jun 26, 2004 at 04:38 UTC
I think you've landed in a sand trap. When I run these in Perl 5.8.1 they perform one iteration and stop. The problem is that you're changing the value of $x in the while condition and the left-hand side of the subtraction can return either the new value or the old value. In my case it's returning the new value which causes the loop to terminate early. Update: These work for me. I've skipped printing the newline to lower the golf score by 6. I wasn't able to skip the initial assignment but that only saves 1 character anyway. `$;=3;$_=$;while($;-=sin$;/cos$;)-$_;print $;=2;$_=$;while($;+=(1-log$;)*$;)-$_;print` [download]	[reply] [d/l]

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Re^2: Deriving pi and e
by jdalbec (Deacon) on Jun 26, 2004 at 04:38 UTC

Update: These work for me. I've skipped printing the newline to lower the golf score by 6. I wasn't able to skip the initial assignment but that only saves 1 character anyway.

$;=3;$_=$;while($;-=sin$;/cos$;)-$_;print

$;=2;$_=$;while($;+=(1-log$;)*$;)-$_;print
[download]

[reply]
[d/l]