in reply to Re: Resolving scalars in a scalar
in thread Resolving scalars in a scalar

So after mindlessly fiddling with the eval statement, I came up with the following; 
my $alpha = "A";
my $delta = "D";
my $test = "$delta and $alpha";
eval "\$test = \"$test\"";
print "$test";

[download]
Is that... right?

Is it fair to stick a link to my site here?

Thanks for you patience.

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Re: Re: Re: Resolving scalars in a scalar
by Roger (Parson) on Oct 31, 2003 at 04:03 UTC
    Ummm, because your $test is quoted inside double quote, your $test = "D and A" even before you go into the eval, so the eval had no effect.

    Change the code slightly as follows -
    my $alpha = "A";
my $delta = "D";
my $test = '$delta and $alpha';
eval "\$test = \"$test\"";
print "$test";

    [download]
    and yes, it will work this time, because the code is equivalent to -
    my $alpha = "A";
my $delta = "D";
my $test = '$delta and $alpha';
$test = "$delta and $alpha";
print "$test";

    [download]
    Where the variable $test inside double quote " " has been expanded by the perl interpreter to the value of $test before going into eval

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