in reply to Re: comparing array elements
in thread comparing array elements

the hash backfired! so i'm using a for loop. (little success so far) my comparison operator isn't working (both arrays contain 4- letter words) and i just need to determine which words are contained in the same position in each array.

thanks for helping!

for (my $i =0; $i < @forward_tets; $i++)   {

           if ($forward_tets[$i] =~ $reverse_tets[$i])  {
                      print "$forward_tets[$i] \t $reverse_tets[$i]\n"
+;
           }
}

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Re: comparing array elements
by Abigail-II (Bishop) on Nov 21, 2003 at 09:51 UTC
    To compare two strings for equality, one uses eq, not =~ (although, if the words just contain letters, it would work too).

    Abigail

[reply]
      yep, but this loop seems to be comparing every position in the first array to every position in the second, not one at a time! How can I do this?
[reply]

        Why do you need two for-loops? Wouldn't one work?

        my @array1 = ('test', 'text', 'next');
my @array2 = ('text', 'test', 'next');
for (my $i=0; $i < scalar(@array1); $i++) {
    if ($array1[$i] eq $array2[$i]) {
        print "$array1[$i] matches\n";
        }
    }

        [download]
[reply]
[d/l]
        How's that possible? You index both arrays with the same key.

        Abigail

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