my @c = @a or @b;
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That's not the same, the asignment has more precedence than the or.

And Deparse tells that the only difference between "or" and "||" are two parents:

perl -MO=Deparse,-p -e 'my @d = (@a or @b);'
(my(@d) = (@a || @b));
-e syntax OK
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and it's evaluated in scalar context.

$anarion=\$anarion;

s==q^QBY_^=,$_^=$[x7,print