in reply to Re: spinner to keep the patiently waiting user patient
in thread spinner to keep the patiently waiting user patient
On my computer, in a tight loop, you could reach this point in just 30 years :)$ perl -we'$x = $y = 2**53-1; ++$x; print $x-$y' 1 $ perl -we'$x = $y = 2**53; ++$x; print $x-$y' 0
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Re: Re: Re: spinner to keep the patiently waiting user patient
by RMGir (Prior) on Dec 08, 2003 at 19:26 UTC | |
by rob_au (Abbot) on Dec 08, 2003 at 22:05 UTC |