in reply to (s)printf question: eliminating plus sign before zeros

There is no printf format which does that, so far as I know. Your solution is about what you need to do. It can be simplified a bit, printf +( $_ ? '%+4d' : '%4d' ), $_ for @nums;

After Compline,
Zaxo

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Re: Re: (s)printf question: eliminating plus sign before zeros
by Not_a_Number (Prior) on Dec 17, 2003 at 22:04 UTC

    Zaxo++

    In fact, playing with your solution, I can 'simplify' it further

    printf $_ ? '%+4d' : '%4d', $_ for @nums;

    But that's starting to look like golf...

    dave

[reply]
[d/l]

      Did someone mention golf:) 

      printf $_ ? '%+4d' : '   0', $_ for -4 .. +4;
  -4  -3  -2  -1   0  +1  +2  +3  +4

      [download]

      Actually it doesn't shorten the code any, but it maybe saves a few microseconds in parsing, both by the computer and the human being. Maybe?

      Examine what is said, not who speaks.
      "Efficiency is intelligent laziness." -David Dunham
      "Think for yourself!" - Abigail
      Hooray!
[reply]
[d/l]

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