in reply to Re: SCALAR output instead of attribute name.
in thread SCALAR output instead of attribute name.

You're assigning a refernce to an array into an array.

Ummm, no. He's assigning a list of references into an array.

#!/usr/bin/perl -l my @a = qw(a b c); my @b = \(@a); print "\@a contains: @a"; print "\@b contains: @b"; __END__ @a contains: a b c @b contains: SCALAR(0x811b15c) SCALAR(0x811b240) SCALAR(0x811b294)

What you are thinking of is [ LIST ].