in reply to 'nother P(erl|ython) Hacker
;$*=1000;$@=int rand$*;sub _{print@_}$%= $*/2;for(;$%!=$@;$-++){;($%>$@)?$*=$%:$: =$%;$%=int(($%>$@)?$%-(($*-$:)/2):$%+($* -$:)/2);}_("Answer is $% ($- tries)\n"); [download]