Re: array sorting

You could do what the others are doing, but I personally don't understand either. I ran all your examples and now I'm wondering why when you treat a scalar as a list, it doesn't get sorted..but as a string, it does. Then the other people are joining on the scalar as if it were a string, I'm not sure I understand that either.

How I do it is a little different:

for (sort @animals) { print "$_ "; }
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UPDATE: Well what do you know, without realizing it I didn't interpolete(sp) @animals either.. But I still understand this better than joining a a blank line on a string (how does it know where the spaces are to be printed?)

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Re: Re: array sorting by davido (Cardinal) on Jan 29, 2004 at 07:46 UTC
Take a deep breath and look at it again. `@sorted = sort @unsorted; $string = join " ", @sorted; print $string;` [download] That's the same as.... `print join( " ", sort @unsorted );` [download] Except that you're not using two intermediate variables. sort takes a list or array as input, and spits out a sorted list which you can either slurp into an array, or send into the input side of join. join takes a list or array as input, and joins its elements together with whatever you put between the quotes, to create a single big-old string. print takes a list (even if the list is one element... and in this case the one element is the string which is the output of join). Hope this helps... Dave	[reply] [d/l] [select]

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Re: Re: array sorting
by davido (Cardinal) on Jan 29, 2004 at 07:46 UTC

@sorted = sort @unsorted;
$string = join " ", @sorted;
print $string;
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That's the same as....

print join( " ", sort @unsorted );
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Except that you're not using two intermediate variables. sort takes a list or array as input, and spits out a sorted list which you can either slurp into an array, or send into the input side of join. join takes a list or array as input, and joins its elements together with whatever you put between the quotes, to create a single big-old string. print takes a list (even if the list is one element... and in this case the one element is the string which is the output of join).

Hope this helps...

Dave

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