in reply to Operator for "these expressions, in any order"

/(?=.*X)(?=.*Y)(?=.*Z)/

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Although you might have to constrain the .* to something nicer.

-- Randal L. Schwartz, Perl hacker
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Re: •Re: Operator for "these expressions, in any order"
by Roger (Parson) on Feb 17, 2004 at 15:52 UTC
    Just another Randal... I like this solution better. :-)

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Re: Operator for "these expressions, in any order"
by Abigail-II (Bishop) on Feb 17, 2004 at 16:15 UTC
    That would match on "XYZZ", of which I got the impression the OP doesn't want a match.

    Abigail

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