in reply to Serial I/O and time question
$SIG{ALRM} = \&timeout_code; alarm = $N; while (<COM>) { $out .= <COM>; } $SIG{ALRM} = "";
-Mark
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Re: Re: Serial I/O and time question
by shepner (Initiate) on Feb 20, 2004 at 00:41 UTC |