Re: Re: How to swap scalar values without copies

(I see now the update, and I don't know how to update my reply in turn ...).

Swapping the values of the references does not waste memory, but it violates rule n.2, namely that I want $a to be a string, not a reference to a string.

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Re: Re: Re: How to swap scalar values without copies by hardburn (Abbot) on Feb 20, 2004 at 00:16 UTC
I don't think you can have it both ways. You either need to work around having a reference or live with the major memory requirement. I'm not an XS-guru, but it appears Data::Swap just does the reference stuff for you. ---- `: () { :\|:& };:` Note: All code is untested, unless otherwise stated	[reply] [d/l]
Re: Re: Re: How to swap scalar values without copies by Anonymous Monk on Feb 20, 2004 at 02:04 UTC
That is a very stupid requirement. You're creating a problem where one doesn't exist.	[reply]
Stupid requirements by Anonymous Monk on Feb 20, 2004 at 02:22 UTC
Thanks for your insightful contribution	[reply]