No, that's not true. Lists do not exist in scalar or boolean context.

$a = (3,2,1);
print $a;  # 1
[download]

Read my article ("List is a Four-Letter Word") at my web site for stuff I'd rather not rewrite here.

perl -e '$val = () = (10,20,30); print $val'
[download]

prints 3.

$_="goto+F.print+chop;\n=yhpaj";F1:eval