When you pass arguments to a subroutine, they are passed in via the special array @_. To get them back into named scalars, assign that to the name(s) you want:

my $html = "hello";

routine( $html );

sub routine{
    my( $arg1 ) = @_;
    print $arg1;
}

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NOTE: the variable name $arg1 is just an example.

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In reply to Re: subroutine scalar string input by BrowserUk
in thread subroutine scalar string input by robertw

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