With the ~~ operator having much higher precedence than the comma, this is parsed as a comma-list of a smart-match whose result doesn't matter, more stuff that doesn't matter at all, and "c" which is true.

The second one would pass "x" to the sub which again evaluates a comma-list and throws away everything (including the argument) but "c" which gets returned and is true.

In reply to Re^3: ~~ and list literal by mbethke
in thread ~~ and list literal by Anonymous Monk

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