Why does "x" ~~ "a", "b", "c" always give 1?

It doesn't; it evaluates to "c".

"," is a very low precedence operator. "x" ~~ "a", "b", "c" means ("x" ~~ "a"), "b", "c", which evaluates to "c" in scalar context.

And why does "x" ~~ sub { "a", "b", "c" } also give 1?

It doesn't; it evaluates to "c".

"x" ~~ sub { "a", "b", "c" } is the same as scalar( sub { "a", "b", "c" }->($x) ). Since  "a", "b", "c" evaluates to "c" in scalar context, that is what is returned.

In reply to Re^3: ~~ and list literal by ikegami
in thread ~~ and list literal by Anonymous Monk

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