Boolean context does not first convert the scalar to a number

Ah, I see.

No, at least part of your testing was flawed. "0 ", "0\n", "00", and even "0.0" are all true values. The only false values are "" and "0", period.

perl -e "print (0+qq(0 )?'true':'false')"
perl -e "print (qq(0\n)?'true':'false')"

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What am I doing wrong? It looks like "0 " is indeed false, while "0\n" is true.

Update: I didn't notice I still had the 0+ in there. I tried a bunch of variations. That's what I get for experimenting at 2am!

—John

In reply to Re: (tye)Re: Why isn't "0\n" false? by John M. Dlugosz
in thread When does $_ get used? by elbie

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