It depends what you're doing really. In your example, join beats concat, but that's because you are looping through an array. Here though, concatenation beats it (albeit only by about 10%):
use strict;
use warnings;
use Benchmark qw{ cmpthese };
sub foo { 'abc' };
sub bar { 'def' };
cmpthese( -3, {
concat => sub { my $ret = foo().bar(); return $ret; },
join => sub { my $ret = join q{}, foo(), bar(); return $ret; },
});
And here (thanks to the Perl compiler being so good at constant folding) concatenation is more than twice as fast as join:
use strict;
use warnings;
use Benchmark qw{ cmpthese };
sub foo () { 'abc' };
sub bar () { 'def' };
cmpthese( -3, {
concat => sub { my $ret = foo . bar; return $ret; },
join => sub { my $ret = join q{}, foo, bar; return $ret; },
});
perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'
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