does the "." operator change the buffers or not?
T.I.T.S. Or, Try It To See.: 
# perl -E '$s .= chr for 0 .. 31; say $s' | xxd
0000000: 0001 0203 0405 0607 0809 0a0b 0c0d 0e0f  ................
0000010: 1011 1213 1415 1617 1819 1a1b 1c1d 1e1f  ................
0000020: 0a

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I'll have no time to benchmark
I am afraid we will have no time to answer.
لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ

In reply to Re^3: How to concatenate N binary buffers? by choroba
in thread How to concatenate N binary buffers? by mantager

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