... move it pairwise along the string (bubble it).

As I understand it, this won't work because substitution is not being done on the original string during the actual substitution process; rather, an intermediate string is being built up during this process, and the intermediate string is copied to the original string when the process is complete.

That's why something like
    ($x = $y) =~ s{foo}{bar}xms;
works as it does: instead of copying the intermediate back to the original string ($y), it's copied to another string ($x) leaving the original string untouched. (Or maybe $x is just used as the 'intermediate' in the first place. Whatever...)

In reply to Re: rotate a vector with a regex? by AnomalousMonk
in thread rotate a vector with a regex? by misterperl

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