HyperZonk's way of doing it is much better, but if you didn't want to do "math" (and I'm really not sure why), you could use chop. It's much uglier, cumbersome and all around a worse method.. but in spirit of TIMTOWTDI..
#!/usr/bin/perl -w use strict; my $foo; $foo = 1500; print myformat($foo, 2) . "\n"; sub myformat { my ($number, $places) = @_; my $decimal; $decimal = ""; for (1 .. $places) { if ($number) { $decimal .= chop $number; } else { $decimal .= 0; } } return "$number\." . reverse $decimal; }
Update: Changed this to be a sub so it doesn't munge the original value as suggested by HyperZonk.

I also added the reverse because I no-so-brillantly forgot that the decimals would be reversed.

Rich


In reply to Re: Help with decimals by rchiav
in thread Help with decimals by La12

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