... An lvalue context is a context where an expression must produce an lvalue ...

That is confusing, the $1 in  bar = "$1" + foo(); is not a location where you can assign (use = ) a value , what?

No, it's stupid to do $x = "$1";

Eh?

In reply to Re^6: $1 not "freezing" in an addition by Anonymous Monk
in thread $1 not "freezing" in an addition by grondilu

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